(5х-1)(2-х)=(х-3)(2-5х)

To solve this equation, we can start by expanding the expressions on both sides.

Expanding the left side of the equation: (5х - 1)(2 - х) = (5х)(2) + (5х)(-х) + (-1)(2) + (-1)(-х) = 10х - 5х^2 - 2 + х = -5х^2 + 11х - 2

Expanding the right side of the equation: (х - 3)(2 - 5х) = (х)(2) + (х)(-5х) + (-3)(2) + (-3)(-5х) = 2х - 5х^2 - 6 + 15х = -5х^2 + 17х - 6

Now, we can set the expanded expressions equal to each other:

-5х^2 + 11х - 2 = -5х^2 + 17х - 6

Since the quadratic terms are the same, we can subtract -5х^2 from both sides to eliminate them:

11х - 2 = 17х - 6

Next, we can subtract 11х from both sides:

-2 = 6х - 6

To isolate the variable х, we can add 6 to both sides:

4 = 6х

Finally, to solve for х, we can divide both sides by 6:

х = 4/6

Simplifying the right side:

х = 2/3

Therefore, the solution to the equation (5х - 1)(2 - х) = (х - 3)(2 - 5х) is х = 2/3.