(5х+1)×(2х-3)=(10х-3)×(х+1)

To solve the given equation, let's expand both sides:

(5x + 1)(2x - 3) = (10x - 3)(x + 1)

Expanding the left side:

(5x + 1)(2x - 3) = 10x^2 - 15x + 2x - 3

Simplifying further:

10x^2 - 15x + 2x - 3 = 10x^2 - 13x - 3

Expanding the right side:

(10x - 3)(x + 1) = 10x^2 + 10x - 3x - 3

Simplifying further:

10x^2 + 10x - 3x - 3 = 10x^2 + 7x - 3

Now, let's equate the two sides of the equation to find the value of x:

10x^2 - 13x - 3 = 10x^2 + 7x - 3

10x^2 - 10x^2 - 13x - 7x = -3 + 3

-20x = 0

Dividing both sides by -20:

x = 0

Therefore, the solution to the given equation is x = 0.