To solve the equation (7x-1)×(x+5) = (3+7x)×(x+3), we can begin by expanding both sides of the equation:
Expanding the left side:
(7x-1)×(x+5) = 7x×x + 7x×5 - 1×x - 1×5 = 7x² + 35x - x - 5 = 7x² + 34x - 5
Expanding the right side:
(3+7x)×(x+3) = 3×x + 3×3 + 7x×x + 7x×3 = 3x + 9 + 7x² + 21x = 7x² + 24x + 9
Now, we have the equation:
7x² + 34x - 5 = 7x² + 24x + 9
To solve for x, we can begin by getting all the terms on one side of the equation:
7x² + 34x - 5 - 7x² - 24x - 9 = 0
Combining like terms:
10x - 14 = 0
To isolate x, we can add 14 to both sides:
10x = 14
Then, divide both sides by 10:
x = 14/10
Simplifying the fraction:
x = 7/5
So the solution to the equation is x = 7/5.
