4x2-5x=y 8x-10=y

To solve this system of equations, we can set the right sides of both equations equal to each other:

4x^2 - 5x = 8x - 10

Rearrange the equation to set it equal to zero:

4x^2 - 5x - 8x + 10 = 0

Combine like terms:

4x^2 - 13x + 10 = 0

Now, we can factor this quadratic equation:

(2x - 5)(2x - 2) = 0

Setting each factor equal to zero, we get two possible values for x:

2x - 5 = 0 2x = 5 x = 5/2

2x - 2 = 0 2x = 2 x = 1

So the solutions for x are x = 5/2 and x = 1.

To find the corresponding values of y, substitute these x values back into one of the original equations. Let's use the second equation:

8x - 10 = y

For x = 5/2: 8(5/2) - 10 = y 20 - 10 = y y = 10

For x = 1: 8(1) - 10 = y 8 - 10 = y y = -2

So the solutions to the system are (5/2, 10) and (1, -2).