Sin 48º + sin 12°

To find the sum of sin 48° and sin 12°, we can use the sum-to-product formula:

sin A + sin B = 2sin((A + B) / 2)cos((A - B) / 2)

In this case, A = 48° and B = 12°. Plugging these values into the formula, we get:

sin 48° + sin 12° = 2sin((48 + 12) / 2)cos((48 - 12) / 2) = 2sin 30°cos 18° = 2(0.5)(0.951) = 0.951

Therefore, sin 48° + sin 12° = 0.951.