(2 8/15-1 5/18-3 1/5)

To subtract fractions with mixed numbers, we first need to convert them into improper fractions.

\(2 \frac{8}{15} = 2 + \frac{8}{15} = \frac{30}{15} + \frac{8}{15} = \frac{38}{15}\)

\(1 \frac{5}{18} = 1 + \frac{5}{18} = \frac{18}{18} + \frac{5}{18} = \frac{23}{18}\)

\(3 \frac{1}{5} = 3 + \frac{1}{5} = \frac{15}{5} + \frac{1}{5} = \frac{16}{5}\)

Now the equation becomes:

\(\frac{38}{15} - \frac{23}{18} - \frac{16}{5}\)

Next, we need to find a common denominator for all the fractions, which in this case is 90.

\(\frac{38}{15} = \frac{38 \times 6}{15 \times 6} = \frac{228}{90}\)

\(\frac{23}{18} = \frac{23 \times 5}{18 \times 5} = \frac{115}{90}\)

\(\frac{16}{5} = \frac{16 \times 18}{5 \times 18} = \frac{288}{90}\)

Now the equation becomes:

\(\frac{228}{90} - \frac{115}{90} - \frac{288}{90}\)

Subtract the numerators:

\(\frac{228 - 115 - 288}{90} = \frac{-175}{90}\)

Finally, simplify the fraction:

\(\frac{-175}{90} = -\frac{35}{18}\)

Therefore, the result is \(-\frac{35}{18}\).