Let's assume the length of the rectangle is x cm and the width is y cm.
The perimeter of a rectangle is given by 2(length + width). From the given information, we can write the equation:
2(x + y) = 22
Simplifying the equation, we get:
x + y = 11 ----- Equation 1
The area of a rectangle is given by length * width. From the given information, we can write the equation:
x * y = 30
Now, we have a system of equations. We can solve it using different methods like substitution or elimination.
Let's use substitution to solve it.
From Equation 1, we have:
x = 11 - y
Substituting this value in the second equation:
(11 - y) * y = 30
Expanding and simplifying:
11y - y^2 = 30
Rearranging the equation:
y^2 - 11y + 30 = 0
This is a quadratic equation. We can solve it by factoring or using the quadratic formula.
Factoring the equation, we get:
(y - 5)(y - 6) = 0
So, either y - 5 = 0 or y - 6 = 0
If y - 5 = 0, then y = 5 If y - 6 = 0, then y = 6
Substituting these values back into Equation 1, we can find the corresponding values of x:
When y = 5: x + 5 = 11 x = 11 - 5 x = 6
When y = 6: x + 6 = 11 x = 11 - 6 x = 5
Therefore, the sides of the rectangle are 6 cm and 5 cm (or vice versa).