2)\ x/3 - y/2 = 1 x/2 + y/5 = 36/5

To solve the system of equations:

1. x/3 - y/2 = 1
2. x/2 + y/5 = 36/5

Let's start by solving equation 1 for x:

x/3 - y/2 = 1

Multiply by 6 to eliminate fractions:

2x - 3y = 6

Now, solve equation 2 for x:

x/2 + y/5 = 36/5

Multiply by 2 to eliminate fractions:

x + 2y = 72

Next, let's solve the system of equations. We can use the substitution method. From equation 1:

2x - 3y = 6 2x = 3y + 6 x = (3y + 6) / 2

Substitute this expression for x into equation 2:

(3y + 6) / 2 + 2y = 72 3y + 6 + 4y = 144 7y = 138 y = 138 / 7 y = 18

Now, substitute y = 18 back into the expression we found for x:

x = (3 * 18 + 6) / 2 x = (54 + 6) / 2 x = 60 / 2 x = 30

Therefore, the solution to the system of equations is: x = 30 y = 18

Это и есть ответ на ваш вопрос!