Z1=10-j•2ом,z2=8ом,z3=-5+j•3ом

To perform calculations with complex numbers, we need to remember that j is the imaginary unit and is equal to sqrt(-1).

Given: Z1 = 10 - j•2 ohm Z2 = 8 ohm Z3 = -5 + j•3 ohm

Let's perform some operations:

1. Addition: Z_total = Z1 + Z2 + Z3 Z_total = (10 - j•2) + 8 + (-5 + j•3) Z_total = 10 - 2 + 8 - 5 + j•3 - j•2 Z_total = 11 + j

Therefore, the total impedance is 11 + j ohm.

Let me know if you need any other calculations or if you have any questions!