4x2 + 11x - 3 = 0.

To solve the quadratic equation 4x^2 + 11x - 3 = 0, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

In this equation, a = 4, b = 11, and c = -3.

Plugging these values into the formula, we get:

x = (-11 ± √(11^2 - 44(-3))) / (2*4) x = (-11 ± √(121 + 48)) / 8 x = (-11 ± √169) / 8 x = (-11 ± 13) / 8

So, the two solutions for the equation 4x^2 + 11x - 3 = 0 are:

x1 = (-11 + 13) / 8 = 2 / 8 = 0.25

x2 = (-11 - 13) / 8 = -24 / 8 = -3