C2H5OH + 6NaOH + 412→ ..CHI) + ..HCOONa + ...Nal + ...H20

To balance this chemical equation, we need to ensure that the number of each type of atom is the same on both sides of the equation.

Given equation: C2H5OH + 6NaOH + 4I2 → ACHI + BNaCHO2 + CNal + DH2O

Let's count the atoms on each side of the equation:

Left side:

• C: 2 in C2H5OH
• H: 6 in C2H5OH + 6 in NaOH = 12
• O: 1 in C2H5OH + 6 in NaOH = 7
• Na: 6 in NaOH
• I: 4 in 4I2

Right side:

• C: A
• H: D
• O: 1 in BNaCHO2, plus unknown amount in H2O
• Na: B
• I: A
• H: D

To balance the equation:

• Balance iodine (I) atoms by placing a coefficient of 4 in front of the product ACHI.
• Balance sodium (Na) atoms by placing a coefficient of 6 in front of NaCHO2.
• Balance oxygen (O) atoms by placing a coefficient of 4 in front of H2O.

The balanced equation is: C2H5OH + 6NaOH + 4I2 → 4CHI + 6NaCHO2 + 5Nal + 4H2O