C2H5OH + 6NaOH + 412→ ..CHI) + ..HCOONa + ...Nal + ...H20

To balance the chemical equation:

C2H5OH + 6NaOH -> ...CHI + ...HCOONa + ...NaI + ...H2O

First, let's balance the elements one by one.

Balance the sodium (Na) atoms: There are 6 Na atoms on the left side (from 6 NaOH). Therefore, the right side should also have 6 Na atoms. So far we have:

C2H5OH + 6NaOH -> ...CHI + ...HCOONa + ...NaI + ...H2O 6Na 6Na

Next, balance the iodine (I) atoms: There is 1 I atom in NaI. Therefore, we need to have 1 I atom in the product. So far the equation looks like this:

C2H5OH + 6NaOH -> ...CHI + ...HCOONa + NaI + ...H2O 6Na 6Na

Now, let's balance the carbon (C) atoms: There are 2 C atoms in ethanol (C2H5OH). To balance this, we need 1 C atom in the product that contains carbon. We can have carbon in HCOONa. Therefore, now the equation looks like this:

C2H5OH + 6NaOH -> ...CHI + HCOONa + NaI + ...H2O 6Na 6Na

Finally, balance the hydrogen (H) and oxygen (O) atoms: On the left side, we have 6 hydrogen atoms from NaOH and 6 hydrogen atoms from ethanol, so a total of 12 hydrogen atoms. On the right side, we have 2 hydrogen atoms in HCOONa and 2 hydrogen atoms in water, totaling 4 hydrogen atoms. To balance this, we need to have 8 more hydrogen atoms. This can be achieved by adding 4 H2O molecules.

Then, balancing the oxygen atoms, we have 2 oxygen atoms in HCOONa and 4 oxygen atoms in water, totaling 6 oxygen atoms on the right side. The left side has 1 oxygen atom from ethanol, so we need to add 5 more oxygen atoms. This can be done by adding 2 O2 molecules.

The final balanced chemical equation is:

C2H5OH + 6NaOH -> 2CHI + 2HCOONa + NaI + 4H2O + 2O2