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Задача Задача №1246064
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Аноним
06 июля 2024 12:52 · публичный вопрос
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Аноним

20/15+х+20/14-х=3

Нейросеть06 июля 2024 12:52

To solve this equation, we need to first combine like terms on both sides of the equation.

\( \frac{20}{15} + x + \frac{20}{14} - x = 3 \)

Simplify the fractions:

\( \frac{4}{3} + x + \frac{10}{7} - x = 3 \)

Now, combine the terms with x and the constant terms:

\( x - x + \frac{4}{3} + \frac{10}{7} = 3 \)

\( \frac{4}{3} + \frac{10}{7} = 3 \)

To add fractions with different denominators, we need to find a common denominator. In this case, the common denominator is 21:

\( \frac{28}{21} + \frac{30}{21} = 3 \)

\( \frac{58}{21} = 3 \)

Now, to solve for x:

\( x = 3 - \frac{58}{21} \)

\( x = \frac{63}{21} - \frac{58}{21} \)

\( x = \frac{5}{21} \)

Therefore, the solution to the equation is \( x = \frac{5}{21} \).

20/15+х+20/14-х=3
To solve this equation, we need to first combine like terms on both sides of the equation. \( \frac{20}{15} + x + \frac{20}{14} - x = 3 \) Simplify the fractions: \( \frac{4}{3} + x + \frac{10}{7} - x = 3 \) Now, combine the terms with x and the constant terms: \( x - x + \frac{4}{3} + \frac{10}{7} = 3 \) \( \frac{4}{3} + \frac{10}{7} = 3 \) To add fractions with different denominators, we need to find a common denominator. In this case, the common denominator is 21: \( \frac{28}{21} + \frac{30}{21} = 3 \) \( \frac{58}{21} = 3 \) Now, to solve for x: \( x = 3 - \frac{58}{21} \) \( x = \frac{63}{21} - \frac{58}{21} \) \( x = \frac{5}{21} \) Therefore, the solution to the equation is \( x = \frac{5}{21} \).