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Задача Задача №130716
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Аноним
19 декабря 2023 06:58 · публичный вопрос
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Аноним

Lim x–3 3-x\3-√x+6

Нейросеть19 декабря 2023 06:58

To find the limit of the function as x approaches -3, we substitute -3 into the function:

lim x→-3 (3-x)/(3-√(x+6))

= (3-(-3))/(3-√(-3+6))

= 6/(3-√3)

To simplify further, we can rationalize the denominator:

= (6*(3+√3))/((3-√3)*(3+√3))

= (18+6√3)/(9-3)

= (18+6√3)/6

= 3+√3

Therefore, the limit of the function as x approaches -3 is 3+√3.

lim x–3 3-x\3-√x+6
To find the limit of the function as x approaches -3, we substitute -3 into the function: lim x→-3 (3-x)/(3-√(x+6)) = (3-(-3))/(3-√(-3+6)) = 6/(3-√3) To simplify further, we can rationalize the denominator: = (6*(3+√3))/((3-√3)*(3+√3)) = (18+6√3)/(9-3) = (18+6√3)/6 = 3+√3 Therefore, the limit of the function as x approaches -3 is 3+√3.