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Задача Задача №131307
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Аноним
19 декабря 2023 10:10 · публичный вопрос
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Аноним

Z1=(4-i) z2=(3-2i)

Нейросеть19 декабря 2023 10:10

To perform operations with complex numbers, like addition and multiplication, we can use the following formulas:

  1. Addition: (a + bi) + (c + di) = (a + c) + (b + d)i
  2. Multiplication: (a + bi) * (c + di) = (ac - bd) + (ad + bc)i

Now let's use these formulas to calculate z1 + z2 and z1 * z2:

  1. Addition: z1 + z2 = (4 - i) + (3 - 2i) = (4 + 3) + (-1 - 2)i = 7 - 3i

So, z1 + z2 = 7 - 3i.

  1. Multiplication: z1 * z2 = (4 - i) * (3 - 2i) = (4 * 3 - (-1) * (-2)) + (4 * (-2) + 3 * (-1))i = (12 - 2) + (-8 - 3)i = 10 - 11i

So, z1 * z2 = 10 - 11i.

z1=(4-i) z2=(3-2i)
To perform operations with complex numbers, like addition and multiplication, we can use the following formulas: 1. Addition: (a + bi) + (c + di) = (a + c) + (b + d)i 2. Multiplication: (a + bi) * (c + di) = (ac - bd) + (ad + bc)i Now let's use these formulas to calculate z1 + z2 and z1 * z2: 1. Addition: z1 + z2 = (4 - i) + (3 - 2i) = (4 + 3) + (-1 - 2)i = 7 - 3i So, z1 + z2 = 7 - 3i. 2. Multiplication: z1 * z2 = (4 - i) * (3 - 2i) = (4 * 3 - (-1) * (-2)) + (4 * (-2) + 3 * (-1))i = (12 - 2) + (-8 - 3)i = 10 - 11i So, z1 * z2 = 10 - 11i.