Решите уравнение: (3x-4) (2x+5)=4x-14+(3x-2).

(3x-4)(2x+5) = 4x-14+(3x-2)

6x^2 + 15x - 8x - 20 = 4x - 14 + 3x - 2

6x^2 + 7x - 20 = 7x - 16

6x^2 + 7x - 7x - 20 + 16 = 0

6x^2 - 4 = 0

3x^2 - 2 = 0

Решение: x = ±√(2/3)