Z1=(6-i) z2=(-3-3i)

Question 1

Задача Задача №134531

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Аноним

20 декабря 2023 02:45 · публичный вопрос

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Аноним 20 декабря 2023 02:45

Z1=(6-i) z2=(-3-3i)

Answer

To find the sum and product of the given complex numbers, let z1 = (6 - i) and z2 = (-3 - 3i).

Sum of the complex numbers: z1 + z2 = (6 - i) + (-3 - 3i) = 6 - i - 3 - 3i = (6 - 3) + (-1i - 3i) = 3 - 4i Therefore, the sum of z1 and z2 is 3 - 4i.
Product of the complex numbers: z1 * z2 = (6 - i) * (-3 - 3i) = -18 - 18i + 3i + 3 = (-18 + 3) + (-18i + 3i) = -15 - 15i Therefore, the product of z1 and z2 is -15 - 15i.

Question 2

z1=(6-i) z2=(-3-3i)

Answer

To find the sum and product of the given complex numbers, let z1 = (6 - i) and z2 = (-3 - 3i). 1. Sum of the complex numbers: z1 + z2 = (6 - i) + (-3 - 3i) = 6 - i - 3 - 3i = (6 - 3) + (-1i - 3i) = 3 - 4i Therefore, the sum of z1 and z2 is 3 - 4i. 2. Product of the complex numbers: z1 * z2 = (6 - i) * (-3 - 3i) = -18 - 18i + 3i + 3 = (-18 + 3) + (-18i + 3i) = -15 - 15i Therefore, the product of z1 and z2 is -15 - 15i.