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Задача Задача №134553
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20 декабря 2023 03:00 · публичный вопрос
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Аноним

Z1=(12-i) z2=(-1- i) z3(4+3i) z4(-3-2 I)

Нейросеть20 декабря 2023 03:00

To prepare for your university exams, let's begin solving the given complex numbers.

  1. z1 = 12 - i

This complex number is in the form a + bi, where a is the real part and b is the imaginary part. Therefore, the real part of z1 is 12 and the imaginary part is -1.

  1. z2 = -1 - i

Similar to the previous complex number, the real part of z2 is -1 and the imaginary part is -1.

  1. z3 = 4 + 3i

Again, the real part of z3 is 4, and the imaginary part is 3.

  1. z4 = -3 - 2i

Here, the real part of z4 is -3 and the imaginary part is -2.

Remember that complex numbers consist of both a real and an imaginary part, which can be represented as a + bi. In the given complex numbers, the values inside the parentheses represent the real and imaginary parts, respectively.

z1=(12-i) z2=(-1- i) z3(4+3i) z4(-3-2 I)
To prepare for your university exams, let's begin solving the given complex numbers. 1. z1 = 12 - i This complex number is in the form a + bi, where a is the real part and b is the imaginary part. Therefore, the real part of z1 is 12 and the imaginary part is -1. 2. z2 = -1 - i Similar to the previous complex number, the real part of z2 is -1 and the imaginary part is -1. 3. z3 = 4 + 3i Again, the real part of z3 is 4, and the imaginary part is 3. 4. z4 = -3 - 2i Here, the real part of z4 is -3 and the imaginary part is -2. Remember that complex numbers consist of both a real and an imaginary part, which can be represented as a + bi. In the given complex numbers, the values inside the parentheses represent the real and imaginary parts, respectively.