Новая Школа - онлайн-школа подготовки к ЕГЭ
Задача Задача №134565
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Аноним
20 декабря 2023 03:04 · публичный вопрос
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Аноним

Z1=(12-i) z2=(-1- i) z3(4+3i) z4(-3-2 I) z3*z4-z2*z1

Нейросеть20 декабря 2023 03:04

To find the value of (z3 * z4) - (z2 * z1), we need to apply the complex number multiplication and subtraction rules. Let's calculate step by step:

z3 * z4 = (4 + 3i) * (-3 - 2i) = 4 * (-3) + 4 * (-2i) + 3i * (-3) + 3i * (-2i) = -12 - 8i - 9i + 6i^2 (where i^2 = -1) = -12 - 17i - 6 = -18 - 17i

z2 * z1 = (-1 - i) * (12 - i) = -1 * 12 - 1 * (-i) - i * 12 + i * (-i) = -12 + i - 12i - i^2 = -12 + i - 12i - (-1) = -12 + i - 12i + 1 = -11 - 11i

Now we can subtract: (z3 * z4) - (z2 * z1)

= (-18 - 17i) - (-11 - 11i) = -18 - 17i + 11 + 11i (applying subtraction rule) = -7 - 6i

Therefore, (z3 * z4) - (z2 * z1) equals -7 - 6i.

z1=(12-i) z2=(-1- i) z3(4+3i) z4(-3-2 I) z3*z4-z2*z1
To find the value of (z3 * z4) - (z2 * z1), we need to apply the complex number multiplication and subtraction rules. Let's calculate step by step: z3 * z4 = (4 + 3i) * (-3 - 2i) = 4 * (-3) + 4 * (-2i) + 3i * (-3) + 3i * (-2i) = -12 - 8i - 9i + 6i^2 (where i^2 = -1) = -12 - 17i - 6 = -18 - 17i z2 * z1 = (-1 - i) * (12 - i) = -1 * 12 - 1 * (-i) - i * 12 + i * (-i) = -12 + i - 12i - i^2 = -12 + i - 12i - (-1) = -12 + i - 12i + 1 = -11 - 11i Now we can subtract: (z3 * z4) - (z2 * z1) = (-18 - 17i) - (-11 - 11i) = -18 - 17i + 11 + 11i (applying subtraction rule) = -7 - 6i Therefore, (z3 * z4) - (z2 * z1) equals -7 - 6i.