log11 V121

To solve \( \log_{11} 121 \), we can first express 121 as a power of 11.

We know that:

\[ 121 = 11^2 \]

Now we can rewrite the logarithm:

\[ \log_{11} 121 = \log_{11} (11^2) \]

Using the logarithm property \( \log_b (b^a) = a \):

\[ \log_{11} (11^2) = 2 \]

Thus,

\[ \log_{11} 121 = 2 \]

So, the answer is:

\[ \boxed{2} \]