To solve the inequality \( X^2 - (X + 6)(X - 6) > 12X \), let's first simplify the left-hand side.
We can start by expanding \( (X + 6)(X - 6) \):
\[ (X + 6)(X - 6) = X^2 - 36 \]
Now, substituting this back into the inequality, we have:
\[ X^2 - (X^2 - 36) > 12X \]
This simplifies to:
\[ X^2 - X^2 + 36 > 12X \]
or
\[ 36 > 12X \]
Next, we'll rearrange the inequality:
\[ 36 - 12X > 0 \]
This can be rewritten as:
\[ 12X < 36 \]
Now, divide both sides by 12:
\[ X < 3 \]
Thus, the solution to the inequality is:
\[ X < 3 \]
In interval notation, the solution is \( (-\infty, 3) \).