x-121=x·6=половина x

Let's solve the equation you provided step by step.

You have:

\[ x - 121 = x \cdot 6 = \frac{1}{2} x \]

To clarify, it looks like you are stating two equalities:

1. \( x - 121 = x \cdot 6 \)
2. \( x \cdot 6 = \frac{1}{2} x \)

Let's solve each of these equations one by one.

Step 1: Solve \( x - 121 = x \cdot 6 \)

Rearranging the equation gives:

\[ x - 6x = 121 \]

\[ -5x = 121 \]

\[ x = -\frac{121}{5} \]

Step 2: Solve \( x \cdot 6 = \frac{1}{2} x \)

Rearranging the equation gives:

\[ 6x - \frac{1}{2} x = 0 \]

To combine the terms, express \( 6x \) with a common denominator:

\[ \frac{12}{2} x - \frac{1}{2} x = 0 \]

Now, simplify:

\[ \frac{12 - 1}{2} x = 0 \]

\[ \frac{11}{2} x = 0 \]

Thus, \( x = 0 \).

Conclusion

The solutions are:

1. From \( x - 121 = x \cdot 6 \), we found \( x = -\frac{121}{5} \).
2. From \( x \cdot 6 = \frac{1}{2} x \), we found \( x = 0 \).

These are two distinct solutions. If you meant to have them equal to each other or in a different format, please clarify!