6 7/15-2 11/15

To subtract the mixed numbers \(6 \frac{7}{15}\) and \(2 \frac{11}{15}\), follow these steps:

1. Convert the mixed numbers to improper fractions: \[ 6 \frac{7}{15} = \frac{6 \times 15 + 7}{15} = \frac{90 + 7}{15} = \frac{97}{15} \] \[ 2 \frac{11}{15} = \frac{2 \times 15 + 11}{15} = \frac{30 + 11}{15} = \frac{41}{15} \]

2. Now subtract the improper fractions: \[ \frac{97}{15} - \frac{41}{15} = \frac{97 - 41}{15} = \frac{56}{15} \]

3. Convert the improper fraction back to a mixed number: \[ 56 \div 15 = 3 \quad \text{(whole number)} \] \[ 56 - (15 \times 3) = 56 - 45 = 11 \quad \text{(remainder)} \] Thus, we can write: \[ \frac{56}{15} = 3 \frac{11}{15} \]

The final answer is: \[ 3 \frac{11}{15} \]