Новая Школа - онлайн-школа подготовки к ЕГЭ
Задача Задача №1458211
А
Аноним
10 сентября 2024 16:28 · публичный вопрос
А
Аноним

(1+2):3+(4·5)-(6+7+8)

Нейросеть10 сентября 2024 16:28

Let's solve the expression step by step.

The given expression is:

\[ (1+2):3+(4\cdot5)-(6+7+8) \]

  1. First, calculate the values inside the parentheses:

    • \(1 + 2 = 3\)
    • \(6 + 7 + 8 = 21\)
  2. Now, substitute these values back into the expression: \[ 3:3 + (4\cdot5) - 21 \]

  3. Next, calculate \(4 \cdot 5\):

    • \(4 \cdot 5 = 20\)
  4. Substitute this value into the expression: \[ 3:3 + 20 - 21 \]

  5. Now, perform the division:

    • \(3:3 = 1\)
  6. Substitute this value into the expression: \[ 1 + 20 - 21 \]

  7. Now, perform the addition and subtraction:

    • \(1 + 20 = 21\)
    • \(21 - 21 = 0\)

Thus, the final result of the expression is:

\[ \boxed{0} \]

(1+2):3+(4·5)-(6+7+8)
Let's solve the expression step by step. The given expression is: \[ (1+2):3+(4\cdot5)-(6+7+8) \] 1. First, calculate the values inside the parentheses: - \(1 + 2 = 3\) - \(6 + 7 + 8 = 21\) 2. Now, substitute these values back into the expression: \[ 3:3 + (4\cdot5) - 21 \] 3. Next, calculate \(4 \cdot 5\): - \(4 \cdot 5 = 20\) 4. Substitute this value into the expression: \[ 3:3 + 20 - 21 \] 5. Now, perform the division: - \(3:3 = 1\) 6. Substitute this value into the expression: \[ 1 + 20 - 21 \] 7. Now, perform the addition and subtraction: - \(1 + 20 = 21\) - \(21 - 21 = 0\) Thus, the final result of the expression is: \[ \boxed{0} \]