7:2 1/3 + 4:1 1/3

To add the mixed numbers \( 7 \frac{2}{3} \) and \( 4 \frac{1}{3} \), we first convert them to improper fractions.

1. Convert \( 7 \frac{2}{3} \) to an improper fraction: \[ 7 \frac{2}{3} = 7 \times 3 + 2 = 21 + 2 = 23 \] So, \( 7 \frac{2}{3} = \frac{23}{3} \).

2. Convert \( 4 \frac{1}{3} \) to an improper fraction: \[ 4 \frac{1}{3} = 4 \times 3 + 1 = 12 + 1 = 13 \] So, \( 4 \frac{1}{3} = \frac{13}{3} \).

Now, add the two improper fractions: \[ \frac{23}{3} + \frac{13}{3} = \frac{23 + 13}{3} = \frac{36}{3} = 12. \]

Thus, \( 7 \frac{2}{3} + 4 \frac{1}{3} = 12 \).