The number 0.1215(17) represents a decimal with a repeating part. Specifically, it means that the digits "17" repeat indefinitely after "0.1215".
To convert this repeating decimal into a fraction, let's denote the repeating decimal as \( x \):
\[ x = 0.121517171717... \]
To isolate the repeating part, we can multiply \( x \) by a power of 10 that moves the decimal point to the right past the repeating part. Since "17" has 2 digits, we can multiply by 100 (which corresponds to moving the decimal point two places for the repeating part):
\[ 100x = 12.15171717... \]
Now, we can set up another equation to help eliminate the repeat. Multiply \( x \) by 10 to move the non-repeating decimal:
\[ 10x = 1.215171717... \]
Now we subtract the second equation from the first:
\[ 100x - 10x = 12.15171717... - 1.215171717... \]
This simplifies to:
\[ 90x = 11.9365 \]
Now we solve for \( x \):
\[ x = \frac{11.9365}{90} \]
To simplify the fraction, we perform the division:
\[ x = 0.1326 \]
Given the approximation and the original structure of the repeating decimal, you can express it as a fraction. However, for more precise conversion of a repeating decimal, it's best to express the entire decimal (including the repeating part) more clearly.
From here, it might be helpful to further refine or change the form based on the context of your studies, or if there are any particular formats or further calculations you need with this decimal. If this conversion suffices, you can proceed with your exam preparations!
