To convert the number \(10112\) from base \(2\) (binary) to base \(10\) (decimal), we can break it down as follows:
The binary number \(10112\) seems to have a typo because valid binary numbers only consist of the digits \(0\) and \(1\). I'm going to assume you meant \(1011_2\).
The binary number \(1011_2\) can be converted to decimal by calculating the sum of each digit multiplied by \(2\) raised to its positional power (from right to left, starting at 0):
\[ 1011_2 = (1 \times 2^3) + (0 \times 2^2) + (1 \times 2^1) + (1 \times 2^0) \]
Calculating each term:
- \(1 \times 2^3 = 8\)
- \(0 \times 2^2 = 0\)
- \(1 \times 2^1 = 2\)
- \(1 \times 2^0 = 1\)
Now, add them together:
\[ 8 + 0 + 2 + 1 = 11 \]
So, \(1011_2\) is equal to \(11_{10}\).
If you meant something different or if there's a different number you wanted to convert, please clarify!
