Новая Школа - онлайн-школа подготовки к ЕГЭ
Задача Задача №1509541
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Аноним
15 сентября 2024 18:33 · публичный вопрос
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Аноним

10112=х10

Нейросеть15 сентября 2024 18:33

To convert the number \(10112\) from base \(2\) (binary) to base \(10\) (decimal), we can break it down as follows:

The binary number \(10112\) seems to have a typo because valid binary numbers only consist of the digits \(0\) and \(1\). I'm going to assume you meant \(1011_2\).

The binary number \(1011_2\) can be converted to decimal by calculating the sum of each digit multiplied by \(2\) raised to its positional power (from right to left, starting at 0):

\[ 1011_2 = (1 \times 2^3) + (0 \times 2^2) + (1 \times 2^1) + (1 \times 2^0) \]

Calculating each term:

  • \(1 \times 2^3 = 8\)
  • \(0 \times 2^2 = 0\)
  • \(1 \times 2^1 = 2\)
  • \(1 \times 2^0 = 1\)

Now, add them together:

\[ 8 + 0 + 2 + 1 = 11 \]

So, \(1011_2\) is equal to \(11_{10}\).

If you meant something different or if there's a different number you wanted to convert, please clarify!

10112=х10
To convert the number \(10112\) from base \(2\) (binary) to base \(10\) (decimal), we can break it down as follows: The binary number \(10112\) seems to have a typo because valid binary numbers only consist of the digits \(0\) and \(1\). I'm going to assume you meant \(1011_2\). The binary number \(1011_2\) can be converted to decimal by calculating the sum of each digit multiplied by \(2\) raised to its positional power (from right to left, starting at 0): \[ 1011_2 = (1 \times 2^3) + (0 \times 2^2) + (1 \times 2^1) + (1 \times 2^0) \] Calculating each term: - \(1 \times 2^3 = 8\) - \(0 \times 2^2 = 0\) - \(1 \times 2^1 = 2\) - \(1 \times 2^0 = 1\) Now, add them together: \[ 8 + 0 + 2 + 1 = 11 \] So, \(1011_2\) is equal to \(11_{10}\). If you meant something different or if there's a different number you wanted to convert, please clarify!