To solve the expression \( 13h5min - 3 \cdot (2h48min : 6 + 3h47min) \), we'll break it down step by step.
Start with the innermost operation:
- Convert all times into minutes:
- \( 13h5min = 13 \times 60 + 5 = 780 + 5 = 785 \) minutes
- \( 2h48min = 2 \times 60 + 48 = 120 + 48 = 168 \) minutes
- \( 3h47min = 3 \times 60 + 47 = 180 + 47 = 227 \) minutes
- Convert all times into minutes:
Calculate \( 2h48min : 6 \): \[ 168 \text{ minutes} : 6 = \frac{168}{6} = 28 \text{ minutes} \]
Add \( 28 \text{ minutes} \) to \( 3h47min \) (227 minutes): \[ 28 + 227 = 255 \text{ minutes} \]
Now calculate \( 3 \cdot 255 \): \[ 3 \cdot 255 = 765 \text{ minutes} \]
Finally, subtract this from \( 13h5min \) (785 minutes): \[ 785 - 765 = 20 \text{ minutes} \]
Convert back to hours and minutes: Since \( 20 \) minutes is less than an hour, it is simply \( 0h20min \).
Thus, the final result is \( \boxed{0h20min} \).