5940=2•2•3•3•3•5•*

It seems like you're trying to express the prime factorization of the number 5940. Let's break it down:

1. Start with 5940 and divide it by the smallest prime number, which is 2:

   • \( 5940 ÷ 2 = 2970 \)
   • \( 2970 ÷ 2 = 1485 \) (so we have \( 2^2 \))

2. Now, let's work with 1485:

   • \( 1485 ÷ 3 = 495 \)
   • \( 495 ÷ 3 = 165 \)
   • \( 165 ÷ 3 = 55 \) (so we have \( 3^3 \))

3. Now, working with 55:

   • \( 55 ÷ 5 = 11 \) (so we have 5)
   • 11 is a prime number.

Putting this all together, the prime factorization of 5940 can be expressed as:

\[ 5940 = 2^2 \times 3^3 \times 5^1 \times 11^1 \]

So the complete factorization is: \[ 5940 = 2 \cdot 2 \cdot 3 \cdot 3 \cdot 3 \cdot 5 \cdot 11 \]

Thus, the factorization you were trying to convey is:

\[ 5940 = 2^2 \cdot 3^3 \cdot 5 \cdot 11 \]