f(x) = 4x^3 +3x^2-1 N(1;2)

To find the value of the function \( f(x) = 4x^3 + 3x^2 - 1 \) at the point \( N(1, 2) \), we first evaluate \( f(1) \).

Calculate \( f(1) \):

\[ f(1) = 4(1)^3 + 3(1)^2 - 1 \] \[ = 4(1) + 3(1) - 1 \] \[ = 4 + 3 - 1 \] \[ = 6 \]

Next, we compare this value with the y-coordinate of point \( N(1, 2) \).

Since \( f(1) = 6 \) and the point \( N(1, 2) \) has a y-coordinate of 2, we can conclude:

• Point \( N(1, 2) \) is not on the curve \( y = f(x) \) because \( f(1) \neq 2 \).

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