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Задача Задача №1659494
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Аноним
29 сентября 2024 07:12 · публичный вопрос
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Аноним

18m^3*25n/5n^2*12m^2

Нейросеть29 сентября 2024 07:12

To simplify the expression \( \frac{18m^3 \cdot 25n}{5n^2 \cdot 12m^2} \), we start by breaking it down step by step.

  1. Multiply the numerators and denominators: The expression can be rewritten as: \[ \frac{18 \cdot 25 \cdot m^3 \cdot n}{5 \cdot n^2 \cdot 12 \cdot m^2} \]

  2. Calculate the constants:

    • The numerator constants: \[ 18 \cdot 25 = 450 \]
    • The denominator constants: \[ 5 \cdot 12 = 60 \]

    Thus, we have: \[ \frac{450 \cdot m^3 \cdot n}{60 \cdot n^2 \cdot m^2} \]

  3. Now simplify the constants: \[ \frac{450}{60} = 7.5 \]

  4. Simplify the variables:

    • For \(m\): \[ m^{3-2} = m^{1} = m \]
    • For \(n\): \[ n^{1-2} = n^{-1} = \frac{1}{n} \]
  5. Combine these results: So, the simplified expression becomes: \[ 7.5 \cdot m \cdot \frac{1}{n} = \frac{7.5m}{n} \]

Thus, the final simplified expression is: \[ \frac{7.5m}{n} \]

18m^3*25n/5n^2*12m^2
To simplify the expression \( \frac{18m^3 \cdot 25n}{5n^2 \cdot 12m^2} \), we start by breaking it down step by step. 1. **Multiply the numerators and denominators:** The expression can be rewritten as: \[ \frac{18 \cdot 25 \cdot m^3 \cdot n}{5 \cdot n^2 \cdot 12 \cdot m^2} \] 2. **Calculate the constants:** - The numerator constants: \[ 18 \cdot 25 = 450 \] - The denominator constants: \[ 5 \cdot 12 = 60 \] Thus, we have: \[ \frac{450 \cdot m^3 \cdot n}{60 \cdot n^2 \cdot m^2} \] 3. **Now simplify the constants:** \[ \frac{450}{60} = 7.5 \] 4. **Simplify the variables:** - For \(m\): \[ m^{3-2} = m^{1} = m \] - For \(n\): \[ n^{1-2} = n^{-1} = \frac{1}{n} \] 5. **Combine these results:** So, the simplified expression becomes: \[ 7.5 \cdot m \cdot \frac{1}{n} = \frac{7.5m}{n} \] Thus, the final simplified expression is: \[ \frac{7.5m}{n} \]