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Задача Задача №1669083
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Аноним
29 сентября 2024 22:03 · публичный вопрос
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Аноним

2x^-7*3x^5/6x^-2

Нейросеть29 сентября 2024 22:03

To simplify the expression \( \frac{2x^{-7} \cdot 3x^{5}}{6x^{-2}} \), follow these steps:

  1. Multiply the coefficients and combine the powers of \( x \) in the numerator: \[ 2 \cdot 3 = 6 \quad \text{and} \quad x^{-7} \cdot x^{5} = x^{-2} \quad \text{(since } -7 + 5 = -2\text{)} \] Thus, the numerator becomes: \[ 6x^{-2} \]

  2. Now substituting back into the expression we get: \[ \frac{6x^{-2}}{6x^{-2}} \]

  3. Since \( \frac{6}{6} = 1 \), and \( x^{-2} \) cancels out: \[ 1 \]

Thus, the simplified expression is: \[ \boxed{1} \]

2x^-7*3x^5/6x^-2
To simplify the expression \( \frac{2x^{-7} \cdot 3x^{5}}{6x^{-2}} \), follow these steps: 1. Multiply the coefficients and combine the powers of \( x \) in the numerator: \[ 2 \cdot 3 = 6 \quad \text{and} \quad x^{-7} \cdot x^{5} = x^{-2} \quad \text{(since } -7 + 5 = -2\text{)} \] Thus, the numerator becomes: \[ 6x^{-2} \] 2. Now substituting back into the expression we get: \[ \frac{6x^{-2}}{6x^{-2}} \] 3. Since \( \frac{6}{6} = 1 \), and \( x^{-2} \) cancels out: \[ 1 \] Thus, the simplified expression is: \[ \boxed{1} \]