b-(4-2b)+(3b-1)=

Let's simplify the expression step by step:

Given: \[ b - (4 - 2b) + (3b - 1) \]

1. First, distribute the negative sign across the terms in the brackets: \[ b - 4 + 2b + 3b - 1 \]

2. Now, combine like terms: \[ (b + 2b + 3b) + (-4 - 1) \] \[ 6b - 5 \]

So, the simplified expression is: \[ 6b - 5 \]