2x^2+4x-4=x^2+5x+(-3+x^2)

To solve the equation \(2x^2 + 4x - 4 = x^2 + 5x + (-3 + x^2)\), we first simplify the right-hand side.

Starting with the right side:

\[ x^2 + 5x + (-3 + x^2) = x^2 + 5x - 3 + x^2 = 2x^2 + 5x - 3 \]

Now we can rewrite the equation:

\[ 2x^2 + 4x - 4 = 2x^2 + 5x - 3 \]

Next, we subtract \(2x^2\) from both sides:

\[ 4x - 4 = 5x - 3 \]

Now, we can isolate \(x\) by moving all terms involving \(x\) to one side and the constant terms to the other side. Subtract \(4x\) from both sides:

\[ -4 = 5x - 4x - 3 \]

Which simplifies to:

\[ -4 = x - 3 \]

Now, add \(3\) to both sides:

\[ -4 + 3 = x \] \[ -1 = x \]

Thus, the solution is:

\[ \boxed{-1} \]