41•y+144-49+4•y=6•25+80

To solve the equation \( 41y + 144 - 49 + 4y = 6 \cdot 25 + 80 \), we can start by simplifying both sides.

1. Simplify both sides:

   • Left-hand side: \[ 41y + 4y + 144 - 49 = (41y + 4y) + (144 - 49) = 45y + 95 \]
   • Right-hand side: \[ 6 \cdot 25 + 80 = 150 + 80 = 230 \]

2. Rewrite the equation: \[ 45y + 95 = 230 \]

3. Isolate the variable: Subtract 95 from both sides: \[ 45y = 230 - 95 \] \[ 45y = 135 \]

4. Solve for \( y \): Divide both sides by 45: \[ y = \frac{135}{45} = 3 \]

The solution is: \[ \boxed{3} \]