9/16+7/24-3/8

To solve the expression \( \frac{9}{16} + \frac{7}{24} - \frac{3}{8} \), we first need to find a common denominator for the fractions.

The denominators are 16, 24, and 8. The least common multiple (LCM) of these numbers is 48.

Now, we convert each fraction:

1. Convert \( \frac{9}{16} \) to a denominator of 48: \[ \frac{9}{16} = \frac{9 \times 3}{16 \times 3} = \frac{27}{48} \]

2. Convert \( \frac{7}{24} \) to a denominator of 48: \[ \frac{7}{24} = \frac{7 \times 2}{24 \times 2} = \frac{14}{48} \]

3. Convert \( \frac{3}{8} \) to a denominator of 48: \[ \frac{3}{8} = \frac{3 \times 6}{8 \times 6} = \frac{18}{48} \]

Now, we can rewrite the expression: \[ \frac{27}{48} + \frac{14}{48} - \frac{18}{48} \]

Combine the numerators: \[ \frac{27 + 14 - 18}{48} = \frac{23}{48} \]

Thus, the result of \( \frac{9}{16} + \frac{7}{24} - \frac{3}{8} \) is: \[ \frac{23}{48} \]