1/3+х=7/15

To solve the equation \( \frac{1}{3} + x = \frac{7}{15} \), we can isolate \( x \).

1. Start by subtracting \( \frac{1}{3} \) from both sides:

\[ x = \frac{7}{15} - \frac{1}{3} \]

2. To subtract the fractions, we need a common denominator. The denominators are 15 and 3. The least common denominator is 15.

3. Convert \( \frac{1}{3} \) to a fraction with a denominator of 15:

\[ \frac{1}{3} = \frac{1 \times 5}{3 \times 5} = \frac{5}{15} \]

4. Now, substitute that back into the equation:

\[ x = \frac{7}{15} - \frac{5}{15} \]

5. Since the denominators are the same, we can subtract the numerators:

\[ x = \frac{7 - 5}{15} = \frac{2}{15} \]

Thus, the solution is:

\[ x = \frac{2}{15} \]