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Вопрос от +79136612912 Имя 17 октября 2024 01:55

LiOH+CuCl2

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17 октября 2024 01:55

When lithium hydroxide (LiOH) reacts with copper(II) chloride (CuCl₂), a double displacement reaction occurs, resulting in the formation of copper(II) hydroxide (Cu(OH)₂) and lithium chloride (LiCl). The balanced chemical equation for the reaction is:

[ \text{2 LiOH} + \text{CuCl}_2 \rightarrow \text{Cu(OH)}_2 + \text{2 LiCl} ]

Reaction Details:

  • Reactants:

    • Lithium hydroxide (LiOH) is a strong base.
    • Copper(II) chloride (CuCl₂) is a soluble salt.
  • Products:

    • Copper(II) hydroxide (Cu(OH)₂) is typically an insoluble blue precipitate.
    • Lithium chloride (LiCl) is a soluble salt.

Observations:

  • The formation of a blue precipitate (Cu(OH)₂) can be seen immediately after mixing the solutions of lithium hydroxide and copper(II) chloride.

Applications:

  • The reaction can be used in educational settings to demonstrate acid-base reactions, precipitation reactions, or the properties of transition metal compounds.

If you need more detailed information or further assistance on this topic, feel free to ask!

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LiOH+CuCl2
When lithium hydroxide (LiOH) reacts with copper(II) chloride (CuCl₂), a double displacement reaction occurs, resulting in the formation of copper(II) hydroxide (Cu(OH)₂) and lithium chloride (LiCl). The balanced chemical equation for the reaction is: \[ \text{2 LiOH} + \text{CuCl}_2 \rightarrow \text{Cu(OH)}_2 + \text{2 LiCl} \] ### Reaction Details: - **Reactants**: - Lithium hydroxide (LiOH) is a strong base. - Copper(II) chloride (CuCl₂) is a soluble salt. - **Products**: - Copper(II) hydroxide (Cu(OH)₂) is typically an insoluble blue precipitate. - Lithium chloride (LiCl) is a soluble salt. ### Observations: - The formation of a blue precipitate (Cu(OH)₂) can be seen immediately after mixing the solutions of lithium hydroxide and copper(II) chloride. ### Applications: - The reaction can be used in educational settings to demonstrate acid-base reactions, precipitation reactions, or the properties of transition metal compounds. If you need more detailed information or further assistance on this topic, feel free to ask!