Aa BB x aa bb

The genetic cross you've provided, "Aa BB x aa bb," represents a dihybrid cross involving two gene pairs (A and B) where:

• A and a are alleles of the first gene.
• B and b are alleles of the second gene.

Assuming that "A" is dominant over "a" and "B" is dominant over "b", we can analyze the offspring from this cross.

Parental Genotypes:

1. Parent 1: Aa BB
2. Parent 2: aa bb

Gametes Produced:

• Parent 1 can produce the following gametes: AB, Ab
• Parent 2 can produce the following gametes: ab

Punnett Square:

To find the genotypes of the offspring, you can set up a Punnett square:

Resulting Offspring Genotypes:

From the Punnett square, the possible genotypes of the offspring are:

1. AaBb (heterozygous for both traits)
2. Aabb (heterozygous for A and homozygous recessive for B)

Summary of Offspring Ratios:

• 50% AaBb
• 50% Aabb

Phenotypic Ratios:

Assuming "A" and "B" are both dominant traits, the phenotypes would be:

1. AaBb: Dominant phenotype for both traits
2. Aabb: Dominant phenotype for A and recessive phenotype for B

This means that half the offspring would express both dominant traits, while the other half would express the dominant trait for A and the recessive trait for B.

If you have any additional questions or need further information, feel free to ask!