5(4y-6)-3(6y-10)-2y= z-(y+(z-t))=

Let's solve each equation step by step.

First equation:

\( 5(4y - 6) - 3(6y - 10) - 2y = \)

1. Distribute the numbers outside the parentheses: \[ 5 \cdot 4y - 5 \cdot 6 - 3 \cdot 6y + 3 \cdot 10 - 2y \] This simplifies to: \[ 20y - 30 - 18y + 30 - 2y \]

2. Combine like terms: \[ (20y - 18y - 2y) + (-30 + 30) \] Which simplifies to: \[ 0y + 0 \] Therefore, the first equation simplifies to: \[ 0 \]

Second equation:

\( z - (y + (z - t)) = \)

1. Distribute the negative sign: \[ z - y - z + t \]

2. Combine like terms: \[ (z - z) + (t - y) = 0 + (t - y) = t - y \]

Thus, the second equation simplifies to: \[ t - y \]

Summary of Results:

• The first equation simplifies to \( 0 \).
• The second equation simplifies to \( t - y \).