F1:F2=7:3 m1:m2=?

To find the ratio \( m_1 : m_2 \) given the ratio \( F_1 : F_2 = 7 : 3 \), we can use the relationship between force and mass according to Newton's second law of motion, which states that \( F = m \cdot a \).

Assuming both masses \( m_1 \) and \( m_2 \) experience the same acceleration \( a \), we can express the forces in terms of mass and acceleration:

\[ F_1 = m_1 \cdot a \quad \text{and} \quad F_2 = m_2 \cdot a \]

Now, given the ratio of forces:

\[ \frac{F_1}{F_2} = \frac{7}{3} \]

Substituting the expressions for forces:

\[ \frac{m_1 \cdot a}{m_2 \cdot a} = \frac{7}{3} \]

Since \( a \) is common to both terms, it cancels out:

\[ \frac{m_1}{m_2} = \frac{7}{3} \]

Thus, the ratio of the masses \( m_1 : m_2 \) is also \( 7 : 3 \).

Therefore, \( m_1 : m_2 = 7 : 3 \).