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Задача Задача №19267
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29 сентября 2023 08:48 · публичный вопрос
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Найдите x, если lg x=2/5 lg 32-1/3 lg 64+1

Нейросеть29 сентября 2023 08:48

To solve the equation, we'll simplify the expression on the right side first:

lg x = (2/5) lg 32 - (1/3) lg 64 + 1

Using the properties of logarithms, we can simplify further:

lg x = (2/5) lg (2^5) - (1/3) lg (2^6) + 1 lg x = (2/5) * 5 lg 2 - (1/3) * 6 lg 2 + 1 lg x = 2 lg 2 - 2 lg 2 + 1 lg x = 1

Now we can convert the equation back to exponential form:

x = 10^1 x = 10

Therefore, x is equal to 10.

Найдите x, если lg x=2/5 lg 32-1/3 lg 64+1
To solve the equation, we'll simplify the expression on the right side first: lg x = (2/5) lg 32 - (1/3) lg 64 + 1 Using the properties of logarithms, we can simplify further: lg x = (2/5) lg (2^5) - (1/3) lg (2^6) + 1 lg x = (2/5) * 5 lg 2 - (1/3) * 6 lg 2 + 1 lg x = 2 lg 2 - 2 lg 2 + 1 lg x = 1 Now we can convert the equation back to exponential form: x = 10^1 x = 10 Therefore, x is equal to 10.