NaOH+CuNO

When sodium hydroxide (NaOH) reacts with copper(II) nitrate (Cu(NO₃)₂), a double displacement reaction occurs, where the sodium ions (Na⁺) and the copper ions (Cu²⁺) exchange partners with the nitrate ions (NO₃⁻).

The reaction can be summarized as:

\[ \text{2 NaOH} + \text{Cu(NO}_3\text{)}_2 \rightarrow \text{Cu(OH)}_2 + \text{2 NaNO}_3 \]

In this reaction, copper(II) hydroxide (Cu(OH)₂), which is insoluble in water, will precipitate out of the solution. Sodium nitrate (NaNO₃) remains in the solution as it is soluble.

Summary of the products:

• Cu(OH)₂: Precipitate (copper(II) hydroxide)
• NaNO₃: Soluble in aqueous solution (sodium nitrate)

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