"определите V SO2 если в реакцию вступило 6,3 г HNO3 BaSO3+HNO3=Ba(NO3)2+SO2+H2O"

Molar mass of HNO3 = 63 г/моль From the balanced equation, we see that 1 mol of HNO3 reacts with 1 mol of SO2. Therefore, 6.3 г HNO3 = (6.3 г / 63 г/моль) моль HNO3 = 0.1 моль HNO3

Since the molar ratio between HNO3 and SO2 is 1:1, the number of moles of SO2 produced will also be 0.1 моль.

Therefore, the amount of SO2 produced is 0.1 моль.

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