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Задача Задача №2009648
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Аноним
25 октября 2024 06:36 · публичный вопрос
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Аноним

7/18-1/45

Нейросеть25 октября 2024 06:36

To subtract the fractions \( \frac{7}{18} \) and \( \frac{1}{45} \), we need to find a common denominator.

The least common multiple (LCM) of 18 and 45 is 90.

Next, we convert each fraction to have the denominator of 90:

  1. For \( \frac{7}{18} \): \[ \frac{7}{18} = \frac{7 \times 5}{18 \times 5} = \frac{35}{90} \]

  2. For \( \frac{1}{45} \): \[ \frac{1}{45} = \frac{1 \times 2}{45 \times 2} = \frac{2}{90} \]

Now, we can subtract the two fractions: \[ \frac{35}{90} - \frac{2}{90} = \frac{35 - 2}{90} = \frac{33}{90} \]

Next, we simplify \( \frac{33}{90} \) by finding the greatest common divisor (GCD) of 33 and 90, which is 3: \[ \frac{33 \div 3}{90 \div 3} = \frac{11}{30} \]

Thus, the result of \( \frac{7}{18} - \frac{1}{45} \) is \( \frac{11}{30} \).

7/18-1/45
To subtract the fractions \( \frac{7}{18} \) and \( \frac{1}{45} \), we need to find a common denominator. The least common multiple (LCM) of 18 and 45 is 90. Next, we convert each fraction to have the denominator of 90: 1. For \( \frac{7}{18} \): \[ \frac{7}{18} = \frac{7 \times 5}{18 \times 5} = \frac{35}{90} \] 2. For \( \frac{1}{45} \): \[ \frac{1}{45} = \frac{1 \times 2}{45 \times 2} = \frac{2}{90} \] Now, we can subtract the two fractions: \[ \frac{35}{90} - \frac{2}{90} = \frac{35 - 2}{90} = \frac{33}{90} \] Next, we simplify \( \frac{33}{90} \) by finding the greatest common divisor (GCD) of 33 and 90, which is 3: \[ \frac{33 \div 3}{90 \div 3} = \frac{11}{30} \] Thus, the result of \( \frac{7}{18} - \frac{1}{45} \) is \( \frac{11}{30} \).