-3(2-0,4y)+5,6=0,4(3y+1

Let's solve the equation step by step. The equation you've provided is:

\[ -3(2 - 0.4y) + 5.6 = 0.4(3y + 1) \]

First, simplify each side of the equation.

1. Expand the left side:

\[ -3(2 - 0.4y) = -3 \cdot 2 + (-3) \cdot (-0.4y) = -6 + 1.2y \]

So, the left side becomes:

\[ -6 + 1.2y + 5.6 \]

Combine like terms:

\[ -6 + 5.6 = -0.4 \]

Thus, the left side simplifies to:

\[ 1.2y - 0.4 \]

So now the equation looks like:

\[ 1.2y - 0.4 = 0.4(3y + 1) \]

2. Expand the right side:

\[ 0.4(3y + 1) = 0.4 \cdot 3y + 0.4 \cdot 1 = 1.2y + 0.4 \]

Now the equation is:

\[ 1.2y - 0.4 = 1.2y + 0.4 \]

3. Rearrange the equation:

Subtract \(1.2y\) from both sides:

\[ -0.4 = 0.4 \]

This statement is not true, which means there are no solutions to this equation. The left and right sides are contradictory.

Thus, the conclusion is that the equation has no solution.