To solve the equation \( \frac{3}{\frac{2}{3}} = \frac{21}{4} \frac{2}{3} \), let's break it down step by step.
Simplify the left side: \[ \frac{3}{\frac{2}{3}} = 3 \times \frac{3}{2} = \frac{9}{2} \]
Simplify the right side: First, compute \( \frac{21}{4} \times \frac{2}{3} \). \[ \frac{21 \times 2}{4 \times 3} = \frac{42}{12} \] Now simplify \( \frac{42}{12} \): \[ \frac{42 \div 6}{12 \div 6} = \frac{7}{2} \]
Now, we have: \[ \frac{9}{2} = \frac{7}{2} \]
As you can see, \( \frac{9}{2} \) does not equal \( \frac{7}{2} \). Hence, the initial equation \( \frac{3}{\frac{2}{3}} = \frac{21}{4} \frac{2}{3} \) is incorrect.
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