2!+456!

To calculate \(2! + 456!\), first, we need to understand what factorials mean.

The factorial of a non-negative integer \(n\) is the product of all positive integers less than or equal to \(n\).

1. Calculate \(2!\): \[ 2! = 2 \times 1 = 2 \]

2. Now, calculate \(456!\): \(456!\) is a very large number. For most practical purposes, particularly in exams, we usually do not calculate it explicitly, as it's generally more than sufficient to say that \(456!\) is a large number.

Thus, we have: \[ 2! + 456! = 2 + 456! \]

Since \(456!\) is so much larger than \(2\), the sum \(2 + 456!\) will still effectively be \(456!\) for most contexts.

So, the simplified final answer is: \[ 2 + 456! \text{ or } 456! \text{ (emotionally acknowledging that } 2 \text{ is negligible)} \]