Новая Школа - онлайн-школа подготовки к ЕГЭ
Задача Задача №2137465
А
Аноним
07 ноября 2024 17:43 · публичный вопрос
А
Аноним

306•24:72-(35280:7-63•80):97

Нейросеть07 ноября 2024 17:43

Let's break down the expression step by step to solve it.

The expression is:

\[ 306 \cdot 24 : 72 - (35280 : 7 - 63 \cdot 80) : 97 \]

  1. First, we can convert the division and multiplication into fractions as needed and handle them step by step.

Step 1: Solve the first part

\( 306 \cdot 24 \) and then divide by 72:

\[ 306 \cdot 24 = 7344 \]

Now, divide by 72:

\[ 7344 : 72 = \frac{7344}{72} = 102 \]

Step 2: Solve the second part inside the parentheses

First, we need to solve \( 35280 : 7 \):

\[ 35280 : 7 = \frac{35280}{7} = 5040 \]

Next, calculate \( 63 \cdot 80 \):

\[ 63 \cdot 80 = 5040 \]

Now, take these two results and perform the subtraction:

\[ 5040 - 5040 = 0 \]

Step 3: Result from the parentheses

Now we have:

\[ (0) : 97 = 0 \]

Step 4: Finally combine both parts

Now we can put everything together.

\[ 102 - 0 = 102 \]

The final result for the entire expression is:

\[ \boxed{102} \]

306•24:72-(35280:7-63•80):97
Let's break down the expression step by step to solve it. The expression is: \[ 306 \cdot 24 : 72 - (35280 : 7 - 63 \cdot 80) : 97 \] 1. First, we can convert the division and multiplication into fractions as needed and handle them step by step. ### Step 1: Solve the first part \( 306 \cdot 24 \) and then divide by 72: \[ 306 \cdot 24 = 7344 \] Now, divide by 72: \[ 7344 : 72 = \frac{7344}{72} = 102 \] ### Step 2: Solve the second part inside the parentheses First, we need to solve \( 35280 : 7 \): \[ 35280 : 7 = \frac{35280}{7} = 5040 \] Next, calculate \( 63 \cdot 80 \): \[ 63 \cdot 80 = 5040 \] Now, take these two results and perform the subtraction: \[ 5040 - 5040 = 0 \] ### Step 3: Result from the parentheses Now we have: \[ (0) : 97 = 0 \] ### Step 4: Finally combine both parts Now we can put everything together. \[ 102 - 0 = 102 \] The final result for the entire expression is: \[ \boxed{102} \]