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Задача Задача №2138706
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Аноним
07 ноября 2024 18:57 · публичный вопрос
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Аноним

2x-y+5=0

Нейросеть07 ноября 2024 18:57

To solve the equation \(2x - y + 5 = 0\), we need to isolate \(y\) to express it in terms of \(x\).

Starting with the equation:

\[ 2x - y + 5 = 0 \]

We can rearrange it to solve for \(y\):

\[ -y = -2x - 5 \]

Multiplying both sides by -1 gives:

\[ y = 2x + 5 \]

So the equation \(2x - y + 5 = 0\) can be expressed as:

\[ y = 2x + 5 \]

This represents a linear equation in slope-intercept form (\(y = mx + b\)), where the slope \(m = 2\) and the y-intercept \(b = 5\).

If you need further information or specific solutions (like finding the intercepts, graphing, etc.), please let me know!

2x-y+5=0
To solve the equation \(2x - y + 5 = 0\), we need to isolate \(y\) to express it in terms of \(x\). Starting with the equation: \[ 2x - y + 5 = 0 \] We can rearrange it to solve for \(y\): \[ -y = -2x - 5 \] Multiplying both sides by -1 gives: \[ y = 2x + 5 \] So the equation \(2x - y + 5 = 0\) can be expressed as: \[ y = 2x + 5 \] This represents a linear equation in slope-intercept form (\(y = mx + b\)), where the slope \(m = 2\) and the y-intercept \(b = 5\). If you need further information or specific solutions (like finding the intercepts, graphing, etc.), please let me know!