To solve the equation \(2x - y + 5 = 0\), we need to isolate \(y\) to express it in terms of \(x\).
Starting with the equation:
\[ 2x - y + 5 = 0 \]
We can rearrange it to solve for \(y\):
\[ -y = -2x - 5 \]
Multiplying both sides by -1 gives:
\[ y = 2x + 5 \]
So the equation \(2x - y + 5 = 0\) can be expressed as:
\[ y = 2x + 5 \]
This represents a linear equation in slope-intercept form (\(y = mx + b\)), where the slope \(m = 2\) and the y-intercept \(b = 5\).
If you need further information or specific solutions (like finding the intercepts, graphing, etc.), please let me know!
